Subtract SH|AX|B|T|R|AE|K|T S|AX|B|T|R|A|K|T SH|AX|B|T|R|A|K|T fifty five-zero five-o from P|R|AH|M F|R|O|M P|R|O|M the D|AX total T|U|T|AX|L one Just JH|O|S|T JH|AH|SH|T JH|O|SH|T found P|A + UH|N|D F|A + UH|N|JH P|A + UH|N|JH an A|N unusable AX|N|Y|O|Z|AX|B|AX|L AX|N|Y|U|S|AX|B|AX|L AX|N|Y|O|S|AX|B|AX|L box B|U|K|S B|AA|K|SH B|U|K|SH